Beth is using a map. let x represent a distance in cm on the map. to find an actual distance y in kilometers, beth uses the equation y=8x. make a table comparing a distance on the map to actual distance.

-4, -2, 1, 4

step-by-step explanation:

domain = x values

range = y values

27 +27 or 27times 2=54

the diffrence is 0

okay..i will pick 8!

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5