2(x-3)^3(x-3)^2(x+1) find both the x and y intercepts. i have found the x intercepts: -1,2,3 but am struggling to find the y intercepts.

now, the (x-3) is there 5 times,  namely (x-3)(x-3)(x-3) and (x-3)(x-3), that simply means, the root of 3 has a multiplicity of 5, is all

to get the y-intercepts, simple, when the graph touches the y-axis, "x" is zero, thus 

Its d so thats how it would would back from 1.0 form three four two