Solve x2 – 8x + 15 < 0.

select the critical points for the inequality shown.

–15

–5

–3

3

5

x=3,5

x2−8x+15=0

Try to express the terms of the equation in square form.

Adding 16 both sides of the equation,

(x2−2⋅x⋅4+42)+15=16
or,(x−4)2+15−16=0
or,(x−4)2−1=0
or,(x−4)2−12=0

This is the a2−b2=(a+b)(a−b)form.

(x−4+1)(x−4−1)=0
or,(x−3)(x−5)=0

Now, equate both the terms to zero since both of them when multiplied, give zero.

Either,
x−3=0
∴x=3

Or,
x−5=0
∴x=5

Ans:x=3,5   Hope this helpsXD...!!!

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step-by-step explanation:

gedfgb nbgfrezrdfgbn bgfderdfgbvn bvfdsvcb bvfdfgb gfdgb gfr

the first domain and range set to the left is matched with the top relation, and the second set the set in the middle goes with the bottom relation.