What is the midpoint of a segment in the complex plane with endpoints at 6 – 2i and –4 + 6i?

1 + 2i
2 + i
2 + 4i
5 + 4i

Mid point of 6 – 2i and –4 + 6i is 1+2i

A is correct.

Step-by-step explanation:

We are given two complex number and need to find mid point of them

where,

Mid point of 6 – 2i and –4 + 6i

Thus, Mid point of 6 – 2i and –4 + 6i is 1+2i

dd

step-by-step explanation:

dd

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: