Aline of best fit is f(x) ≈ −0.86x + 13.5 for the set of points in the table. using the equation for the line of best fit, what is a good approximation for the value of the function, f(x), when x = 18?
2 12
3 10
5 10
6 8
7 9
8 5
9 6
1. −5
2. −2
3. 3
4. 12

 -2

Step-by-step explanation: f(x)≈ -0.86x+13.5

   putting x=18 in f(x), we get

     f(x)≈ -0.86×18+13.5

  ⇒      f(x)≈ -15.48+13.5

  ⇒      f(x)≈ -1.98

  ⇒      f(x)≈ -2

Option 2 - f(x)=-2

Step-by-step explanation:

Given : A line of best fit is f(x) ≈ −0.86x + 13.5 for the set of points in the table.

2    12

3    10

5    10

6     8

7     9

8     5

9     6

To find :  What is a good approximation for the value of the function, f(x), when x = 18?

Solution :

We have given the function,

The best fit for the value x=18, f(x) is

Approximately, For the value of x=18, f(x)=-2

Therefore, Option 2 is correct.

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)