Abanner is in the shape of a right triangle. the area is 63 inches. the height of the banner is 4 in less than twice the width of the banner. find the height and width of the banner. show all work

Area=1/2 times base times height
note:bh=base times height

a=1/2bh
b=width

h=-4+2w
h=2w-4
subsitute
a=1/2w(2w-4)
a=1/2(2s^2-4w)
a=w^2-2w
a=63
63=w^2-2w
subtract 63 from both sdies
0=w^2-2w-63
factor
find what 2 numbers multiply to get -63 and add to get -2
the numbers are -9 and 7
so
0=(w-9)(w+7)
if xy=0 then x and/or y=0

so
w-9=0
w+7=0

solve each
w-9=0
add 9 to both sdies
w=9

w+7=0
subtract 7 from both sides
w=-7
width cannot be negative so this can be discarded

width=9

subsitute
l=2w-4
l=2(9)-4
l=18-4
l=14

legnth=14 in
width/base=9 in

4hours and 40 mins she would be 120 meters high