The sides of a polygon are 3, 5, 4, and 6. the shortest side of a similar polygon is 9. find the ratio of their perimeters.

Since the shortest side of the first polygon is 3, and the shortest side of the second polygon is 9, then that would make the second polygon 3 times larger. that would make us also be able to say that the other sides of the second polygon would just be multiplied by 3, making the 4 sides be a measure of 9,15,12, and 18