Jason rolls a fair number cube labeled 1 through 6, and then he flips a coin. what is the probability that he rolls a 3 and flips a head?

Probability is 1/12.

Step-by-step explanation:

Since Jason rolls a cube labeled 1 through 6. Then to get any number when he rolls the cube probability will be = 1/6 = One event/ Total number of events

so probability of rolling a 3 = 1/6

Now he flips a coin then probability of getting head will be = 1/2

Since these two events are totally different therefore getting both the events ( getting 3 on rolling cube and flipping for head) will be = P1 × P2

P = (1/6).(1/2) = 1/12

So the answer is P = 1/12.

hc ghfrfgb

step-by-step explanation:

gedfgb nbgfrezrdfgbn bgfderdfgbvn bvfdsvcb bvfdfgb gfdgb gfr

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)