Find the solution to the system of equations given below using elimination by addition.
15x + 15y = 60
5x - 5y = 40

15x + 15y = 60
5x - 5y = 40

To use elimination by addition, you need to get variables in one equation the same but negative in the other equation. For example, to use addition elimination to match the first equation, the second equation has to be - 15x or -15y. 
Luckily, the second equation is easily manipulated to get to -15y.
To go from -5y to -15y you just need to multiply by 3, so we multiply the whole second equation by 3:

3(5x - 5y = 40)
15x - 15y = 120

Now we can add the two equations to "eliminate" the y's
   
   15x + 15 y = 60
+ 15x - 15y = 120
  30x  + 0y = 180

now solve for x: 

30x = 180
divide both sides by 30
x = 6

Now that we solved for x, we can plug it back into the original equations to get y:
15(6) + 15y = 60
90 + 15y = 60
15y = -30
y = -2

5(6) - 5y = 40
30 - 5y = 40
-5y = 10
y = -2

x = 6 and y = -2

5días gucgivuzu 32 horas y horas 6y t7

The question is kind of confusing. if it's asking how many variations of answers can you give. then do 4^5 for your answer.this would be something like the first question could be a and the 2nd c or first b next c etc. if you can, ask the teacher for a better confirmation of what it's asking. if i'm assuming correctly what it's asking, it's 625 different variations.