Given the line 6x-4y=12 find the equation of a parallel line that passes through the point (3,5)

First, we need to find the slope of the line they gave us. To do this we need to put the equation in slope intercept form , where m=slope, and (0,b)=y-intercept.the slope of this line is -5/4. We need a line perpendicular to this line so our slope needs to be 4/5. (Flip the slope and change the sign.) Now we use the point slope formula , where m=slope and (x1,y1)=the given point. Our m=4/5 and our point is (x1,y1)=(3,2)<--slope intercept form of a line