The vertex of a parabola represented by f(x)=x^2 - 4x + 3 has coordinates (2,-1). find the coordinates of the vertex of the parabola defined by g(x)=f(x-2). explain how you arrived at your answer

a=1, b=-4, c=3
If the vertex has coordinates (2;-1)(p=2,q=-1) we can write vertex form of a parabola equation:



We need to put (x-2) at the place of (x) in f(x) equation to get g(x)



So:
p=4, q=-1

Vertex of the parabola defined by g(x)=f(x-2) has the vertex at

:)

The last one bc that's a calendar