When it is 1: 00
a. m. in toronto, it is 3: 00
a. m. in rio de janiero, and when it is 10: 00
a. m. in rio de janiero, it is 11: 00 p. m. in melbourne. you leave toronto to fly to rio de janiero, but you accidentally left your watch on melbourne time. your watch says that you leave toronto at 9: 30
a. m. on saturday. when you arrive in rio de janiero, the local time is 3: 15
a. m. on saturday. how long was your flight?
a. 8 hours, 45 minutes
b. 6 hours, 45 minutes
c. 4 hours, 45 minutes
d. 2 hours, 45 minutes

b. 6 hours, 45 minutes

Step-by-step explanation:

When it is 1:00  a.m. in Toronto, it is 3:00  a.m. in Rio de janiero, and when it is 10:00  a.m. in Rio de janiero, it is 11:00 p.m. in Melbourne. Which means, when it is 8:00 am in Toronto, then it is 11: 00 pm in Melbourne.

2, 2, 2 or -4, 20, 29

step-by-step explanation:

there is two ways you can do it.

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.