An object is launched straight into the air. the projectile motion of the object can be modeled using h(t) = 96t – 16t2, where t is the time since launch and h(t) is the height in feet of the projectile after time t in seconds. when will the object be 144 feet in the air? when will the object hit the ground?

Step-by-step explanation:

We have been the model

Here.  t is the time since launch and h(t) is the height in feet of the projectile after time t in seconds.

For the height of the object to be 144 feet, we have

Therefore, after 3 seconds the object will be 144 feet in the air.

Now, when the object hits the ground then the height should be zero.

Hence, at t= 6 seconds, the object will hit the ground.

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3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.