Complete the following proof related to the figure below.

given:
is the perpendicular bisector of

prove:
∠r = ∠s

which of the following could be statements in line 2 in the proof? select all that apply.

∠1=∠2

∠3=∠4

∠r=∠s

rq=sq

The answer to your quest is RQ=SQ and < R=<S

∠R=∠S and RQ=SQ

Step-by-step explanation:

Given

PQ is the perpendicular bisector of RS, prove  ∠R = ∠S

1. PM is the perpendicular bisector of RS. | Given

2. If M is the midpoint of RS and SQ then RQ = SQ. | Reason: If a point is at a perpendicular bisector line of one segment, that point is equidistant from each endpoint of the line segment.

3. ∠R ≅ ∠S | Reason:  Since PQ is the perpendicular bisector line then we can affirm PS≅ PR and RQ≅SQ as an equal pair of sized segments. That implies equal opposite angle measures of ∠R and ∠S.

4. RQ=SQ | Reason: If Q is the midpoint then RQ has the same size as SQ.

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58