Brynn and denise launch their rockets at the same time. the height of brynn’s rocket, in meters, is given by the function f(x)=-4.9x^2+75x , where x is the number of seconds after the launch.
the height of denise’s rocket, in meters, is given by the function
g(x)=_4.9x^2+50x+38
, where x is the number of seconds after the launch.
there is a moment when the rockets are at the same height.

what is this height?
enter your answer, rounded to the nearest tenth of a meter, in the box.

 102.7 meters

Step-by-step explanation:

Given: Brynn and Denise launch their rockets at the same time.

The height of Brynn’s rocket, in meters, is given by the function , where x is the number of seconds after the launch.  

The height of Denise’s rocket, in meters, is given by the function  

,  where x is the number of seconds after the launch.

The moment when both rockets are on same height, then

It means at 1.52 seconds  the rockets are at the same height.

To calculate the height substitute, the value of x in any of the function.

meters

idk

step-by-step explanation: