Iwill give brainliest answer just plz
jason would like to estimate the probability of heads coming up more than once in 3 coin flips.

to do this, he has a computer randomly select 0 or 1 three times, with 0 representing heads and 1 representing tails. the results of 10 trials are shown in the table.

110 111 100 000 101
111 100 000 011 010

what is jason's estimated probability, based on this simulation?

enter your answer as a fraction, in simplified form, in the box.

Jason's estimated probability, based on this simulation is:

1/2

Step-by-step explanation:

Let 0 represent that head turn up on flipping a coin and 1 represent that tail turn up on flipping a coin.

There are 10 trials whose results are given as:

110111100  000    101

111100000   011     010

Now we are asked to find the probability of heads coming up more than once in 3 coin flips i.e. we have to consider those trials in which there are more than one " 0's ".

Hence, the outcomes that represent the head coming up more than once are:

100  000    100    000   010

Let P denote the probability of an event.

Number of outcomes where head comes up more than once i.e. number of favorable outcomes are: 5.

Total number of outcomes=10

Hence,

Probability( Head comes up more than once)=Number of favorable outcomes/Total number of outcomes.

i.e. Probability( Head comes up more than once)=5/10=1/2

Hence, the estimated probability is:

1/2

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step-by-step explanation:

b.-4 units

all you   do is count how many times you move