If the least value the variable k can be is 12, which of the following inequalities best shows all the possible values of k? k < 12 k > 12 k ≤ 12 k ≥ 12

The correct option is 4. The inequality  k ≥ 12 shows all the possible values of k.

Step-by-step explanation:

It is given that the least value the variable k can be is 12. So, the variable k can take any real value 12 or more than 12.

It means the value of k must be greater than or equal to 12. Mathematically it is can be represented as

The inequality  k ≥ 12 shows all the possible values of k.

Therefore the correct option is 4.

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

what is the answer?