Jason and maria are playing a board game in which three dice are tossed to determine a player's move. find each probability for: p (two 5s) , p (three 5s) , and p (one 5 or two 5s).

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Tossing a die will have 6 possible outcomes. Those are having sides that are number 1 to 6. The sample space of tossing 3 dice is equal to 6³ which is equal to 216. Now for the calculation of probabilities,

P(two 5s) = (1 x 1 x 5)/216
As we have to have the 5 in the die for two times, then for the 1 time, we can have all other numbers except 5. The answer is 5/216. 

P(three 5s) = (1 x 1 x 1)/216   = 1/216

P(one 5 or two 5s)  = (1 x 5 x 5)/216 + (1 x 1 x 5)/216 = 5/36

Yes, that is the correct formula. to solve this problem given the number of years, plug in the number of years for t and plug the whole thing into the