The vertices of an isosceles triangle are a(3, 6), b(7, 2), and c(4, 3). what is the equation of the triangle's line of symmetry?
y = x + 1
y = x - 1
y = x
y = -x + 1

The equation of axis of symmetry of line is y=x-1

B is correct

Step-by-step explanation:

The vertices of an isosceles triangle are A(3, 6), B(7, 2), and C(4, 3)

Distance formula:

AC=BC

Therefore, The vertex of isosceles triangle is C and the line of symmetry passes through point C.

Axis of symmetry line would be perpendicular to the base of triangle.

Slope of base of triangle

Axis of symmetry line is perpendicular to base.  

Thus, The slope of axis of symmetry line is 1 because product of slope of two perpendicular line is -1.

Slope = 1 and passing point: (4,3)

Equation of axis of symmetry:

y-3=1(x-4)

y-3=x-4

y=x-1

Hence, The equation of axis of symmetry of line is y=x-1

the answer is d. (1.2, -4.7) on edgn

hope this !

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