Mathematics, 18.12.2019 23:31 Destinywall

Brian is solving the equation x2-3/4x=5. what value must be added to both sides of the equation to make the left side a perfect-square trinomial?

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Answer from: djgunderson

we have

$x^{2} -\frac{3}{4}x=5$

Divide the term $\frac{3}{4}$ by and then square it

$(\frac{(3/4)}{2})^{2}= \frac{9}{64}$

Add to both sides

$x^{2} -\frac{3}{4}x+\frac{9}{64}=5+\frac{9}{64}$

Rewrite as perfect square

$(x-\frac{3}{8})^{2}=\frac{329}{64}$

therefore

the answer is

$\frac{9}{64}$

Answer from: Quest

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step-by-step explanation:

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

ver más en -

step-by-step explanation:

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