Iknow i already asked this but this time it is 50 points
c=ax-bx
joseph claims that if...
Mathematics, 27.09.2019 11:10 CJohnson9552
Iknow i already asked this but this time it is 50 points
c=ax-bx
joseph claims that if a, b, and c are non-negative integers, then the equation has exactly one solution for x. select all cases that show joseph's claim is incorrect.
a. a-b=1,c=0
b. a=b, c≠0
c. a=b, c=0
d. a-b=1,c≠1
e. a≠b, c=0
Answers: 2
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