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Mathematics, 23.09.2019 08:00 rwbrayan8727

(x+b/2a)^2-b^2-4ac/4a^2=0
what would be the steps to solve this equation?

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Answers: 1

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(x+b/2a)^2-b^2-4ac/4a^2=0
what would be the steps to solve this equation?...
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