The coordinates of the vertices of triangle def are given in the table. d e f (0,7) (2,9) (4,1) triangle def is reflected across the x-axis. what are the vertices of triangle d'e'f'?

The vertices of D'E'F' are (0,-7), (2,-9) and (4,-1).

Step-by-step explanation:

We are given that,

Co-ordinates of triangle DEF are D= (0,7), E= (2,9) and F= (4,1).

The triangle DEF is reflected over x-axis to form triangle D'E'F'.

Now, 'Refection over x-axis changes the co-ordinates (x,y) to (x,-y)'.

So, we get,

Co-ordinates of vertices of triangle D'E'F' are,

D' = (0,-7)

E' = (2,-9)

F' = (4,-1)

Thus, the vertices of D'E'F' are (0,-7), (2,-9) and (4,-1).

4400

step-by-step explanation:

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1