You purchase aquasonic gel for the ultrasound labs in the hospital. a 5-liter bottle costs $20.00. a case (12 tubes/case) of 250-milliliter tubes costs $19.50. your department uses 15 liters per month.

the conversion you will need is: 1 milliliter = .001 liter.

which one produces a cost savings? how much would you save in a month?

a. small tubes, $7.50
b. large bottle, $7.50
c. small tubes, $37.50
d. large bottle $37.50

D

Step-by-step explanation:

A 5 liter bottle costs $20.00. So for every liter you are paying 20/5=$4 per liter.

A case of 250 mililiter tubes cost $19.50 and each case has 12*250=3000 mililiters = 3 liters of gel.

If you need 15 liters per month then the two options would yield the follwing:

Option 1: 5 liter bottles

You would require 3 five liter bottles of r 15 liters, therefore the total cost is:

Option 2: a case of 250 mililiters

You required 5 cases of 250 mililiter tubes, therefore the total cost is:

∴ The best option will be buying the large 5 liter bottles and you will make a saving of $37.5

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!