Suppose a population of 190 crickets doubles in size every month. the function f(x)=190(2^x) gives the population after x months. how many crickets will be there after 1 year

After 1 year population of the crickets will be 778240.

Step-by-step explanation:

Population of crickets is 190 initially which doubles up in one month.

The function represents the population growth is f(x) =

Now we have to calculate the population of the crickets after 1 year.

We will plug in the value of x = 12 months in the function.

f(12) =

      = 190×4096

      = 778240

Therefore, after 1 year population of the crickets will be 778240.

idk

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west