Agolf ball is hit from the ground with an initial speed of 192 feet per second. assume the starting height of the ball is 0 feet. how long will it take the golf ball to hit the ground?
39 secs
19 secs
12 secs
6 secs

The golf ball take 12 seconds to hit the ground.

Thus, option (3) is correct.

Step-by-step explanation:

  We are given,

Initial velocity (u) = 192 feet per second

g be the acceleration due to gravity and its value is  32 feet per second square.

Using Newton's motion of equation

Where, s is displacement of body

            u is initial velocity of body

            a is acceleration of body

             t is time

In question, displacement is in term of height so replacing s by h

and acceleration is done due to gravity so replacing a by g

We get,

Since, displacement is changing with time.

Putting values of u and g we get ,

when ball hit the ground height would be 0.

Therefore, h(t) = 0

⇒ t = 12 secs

Thus, the golf ball take 12 seconds to hit the ground.

So, option (3) is correct.

the axial of symmetry

step-by-step explanation: