Identify all the points that are on the following quadratic function: y = x2 - 3x (0,3) (0,0) (2,-2) (-1,4) (-3,15)

The points on the quadratic function are :

, and

Step-by-step explanation:

We have the following quadratic function :

If we want to see if a particular point is on the quadratic function we need to replace each pair in the quadratic function expression and check the equality.

For example :

We have the following point :

If we replace by and in the quadratic function :

The final expression is false, therefore the point is not on the quadratic function.

Now let's work with the points we were given.

The first point is ⇒ If we replace in the quadratic function :

We conclude that the point is not in the quadratic function.

The second point is

This point is on the quadratic function.

The third point is

If we replace in the quadratic function :

The point is on the quadratic function.

The fourth point is

Therefore the point is on the quadratic function.

Finally, we have the point

If we replace in the quadratic function :

This point is not on the quadratic function.

We conclude that the points and are on the quadratic function

rx and sx

step-by-step explanation: