Two equations are given below:

a − 3b = 16
a = b − 2

what is the solution to the set of equations in the form (a, b)?

(−2, −6)
(−7, −9)
(−11, −9)
(−12, −10)

A − 3b = 16
a = b − 2

b - 2 - 3b = 16
2b = - 18
b = - 9

a = - 9 - 2
a = - 11

(-11,-9)

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*

Sorry i meant b in the other question