An object is thrown off a 256-foot-tall building, and the distance of the object from the ground is measured every second. the function that models the height, h, of the object after t seconds is h(t) = –16t2 + 96t + 256. determine the time when the object hits the ground. after how many seconds does the object hit the ground? a.2 b.4 c. 8 d. 16

C. 8

Step-by-step explanation:

When the object hits the ground, h(t) = –16t^2 + 96*t + 256 = 0. Using the quadratic formula (where a= -16, b=96 and c=256) we get:  

The first root (-2) has no physical sense and is discarded. Then, the object hits the ground after 8 seconds.

i would say b) is your answer

sorry if im wrong

step-by-step explanation:

at least two

step-by-step explanation: