What is a positive coterminal angle to 403° that is between 500° and 1000° and a negative coterminal angle to 403° that is between −500° and 0°?

what is the value of arccos(−0.32) as a decimal to the nearest hundredth of a degree?

Positive co-terminal = 763°

Negative co-terminal = -317°

arccos(-0.32)=108.66°

Step-by-step explanation:

We are given an angle 403°

We need to find Positive co-terminal of angle 403° that is between 500° and 1000°

For positive co-terminal angle add 360°

Positive co-terminal of 403° ⇒ 403+360 ⇒ 763°

500° ≤ 763° ≤ 1000°

Therefore, 763° is positive co-terminal angle of 403° between 500° and 1000°

For negative co-terminal angle subtract 360°

Negative co-terminal of 403° ⇒ 403-360 ⇒ 43°

But 43° is not lie between -500° and 0°

So, we subtract 360° again

Negative co-terminal of 403° ⇒  43°-360° ⇒ -317°

-500° ≤ -317° ≤ 0°

Therefore, -317° is negative co-terminal of 403° between -500° and 0°

# We need to find the value of arccos(−0.32) as a decimal to the nearest hundredth of degree.

Using calculator to find the inverse of cos at -0.32

Therefore, arccos(−0.32)=108.66°

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb