6x + 3y = 9
2x + 3y = 1
solve the system of equations.

6x + 3y = 9
2x + 3y = 1

Subtract the equations from each other.

4x = 8

Divide both sides by 4.

x = 2

Plug in (2) for x in the first equation.

6x + 3y = 9

6(2) + 3y = 9

12 + 3y = 9

Subtract 12 from both sides.

3y = (9-12)

3y = -3

Divide both sides by 3.

y = -1

(2, -1)

~Hope I helped!~

Solution 1: 6(x) + 3(y) = 9
Solution 2: 2(x) + 3(y) = 1
________________________

Your graphic organizer↓
3(y) + 6(x) = 9
3(y) + 2(y)= 1 
_______________________

For the y-intercept; solution 2 ↓
"2" becomes a negative
3(y) which is equal to -2(x) + 1 
Take off the "3" then this becomes y =  + 
_________________________________
Moving on to the x-intercept ; the first solution 
6(x) + 3  = 9
_______________________________
We can simplify to find the x-intercept
4(x) = 8 
the x-intercept is 2
______________________________
Lastly, we are looking for the y-intercept

 
 
So, the y-intercept is: -1 
_______________________________
Answer↓


x-intercept: 2

y-intercept: -1