What is the solution set of this system of equations? y = x2 − 6x + 8 2y + x = 4

This is the solution

2y + x = 4
2y = -x +4
y = -x/2 + 2

y = x^2 -6x + 8 = -x/2 + 2

2x^2 - 12x + 16 = -x + 4
2x^2 -11x +12 = 0

Factor

(x-4)(2x-3)=0

x= 4 and x =3/2

y = -x/2 +2
 
y = -4/2 + 2 = 0
y = - (3/2)/2 + 2 = -3/4 + 2 = 5/4

Answer (4,0) and (3/2, 5/4)

The solution to this system of equations is x=4. y=0. The next one is x=3/2  and y=5/4. Hope this helps!

Ithink the answer is a