Antonio has found that he can input statistical data into his computer at the rate of 2 data items faster each half hour he works. one monday, he starts work at 9: 00a. m., inputting data at a rate of 3 data items per minute. at what rate will antonio be inputting data into the computer by lunchtime (noon)? a. 12 data items per minute c. 21 data items per minute b. 15 data items per minute d. 24 data items per minute

b. 15 data items per minute

Step-by-step explanation:

Given,

The number of data he can input per minute at 9:00 AM = 3,

Since, he inputs data 2 data items faster each half hour,

So, the number of inputted data per minute at 9:30 AM = 3 + 2 = 5,

At 10:00 AM = 5 + 2 = 7,

At 10:30 AM = 7 + 2 = 9,

At 11:00 AM = 9 + 2 = 11,

At 11:30 AM = 11 + 2 = 13,

At 12:00 AM or at noon = 13 + 2 = 15,

Hence, his rate of inputting data at noon is 15 data items per minute.

Option 'b' is correct.

sorry i need the points

step-by-step explanation:

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you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)