3. find the horizontal change and the vertical change for the translation.
p(4, -4) > (-4, 7)
a. right 8; up 11
b. left 8; down 11
c. right 8; down 11
d. left 8; up 11

4. the point c(3, -1) is translated to the left 4 units and up 1 unit.
a. write the rule for the translation
b. what are the coordinates of the image point?
a. (x,> (x+4+1); (7, -2)
b. (x, y) --> (x-4, y -1); (-1, 0)
c. (x,> (x+4, y -1); (7, 0)
d. (x, y) > (x-4, y+1); (-1,0)

5.

1 and 2

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.