Joanna has nickels, dimes, and pennies in a jar. the probability of drawing a nickel from the jar is 0.3, the probability of drawing a dime is 0.2, and the probability of drawing a penny is 0.5. joanna picks a coin from the jar 240 times, replacing each coin before the next draw. about how many times would joanna pick a dime in 240 draws?

The required number of times Joanna would pick a dime in 240 draws = 48

Step-by-step explanation:

The probability of drawing a nickel from the jar is 0.3

The probability of drawing a dime is 0.2

The probability of drawing a penny is 0.5

Also, The total number of times a coin is picked from the jar = 240

Now, we need to find the total number of times Joanna would pick a dime

⇒ The required number of times Joanna would pick a dime = Probability of picking up a dime × Total number of draws

⇒ The required number of times Joanna would pick a dime = 0.2 × 240

⇒ The required number of times Joanna would pick a dime = 48

Therefore, The required number of times Joanna would pick a dime in 240 draws = 48

y-y1=4(x-x1)

step-by-step explanation:

this is point-slope form since you only have 4 as the slope it goes in place of m

hope this : )

no one knows lol

step-by-step explanation: