Mathematics, 31.08.2019 12:00 blondie02

Rectangle is 2/5 in. long and 1/3 in. wide.
what is the area of the rectangle
answer in the form of a fraction

Answers: 1

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Answers

" $\frac{2}{15}$ in² " . {that is: " (2/15) in² . "}.
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Explanation:
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The formula/equation for the Area of a rectangle:

A = L * w ;

in which: L = ⅖ in ;
w = ⅓ in;
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Find the area; in a "fraction value" ;
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A = L * w ;

→ Substitute the given values for "L" (length) and "w" (width);
and solve for "A" (area) in the "form of a fraction:
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A = (2/15) in * (1/3) in ;

→ A = [(2*1) / (5*3)] * in * in ;
______________________________________________________
→ The area is: " $\frac{2}{15}$ in² " .

{that is, "(2/15) in² " .}.
______________________________________________________

Answer from: Quest

1,918

step-by-step explanation:

Answer from: Quest

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

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