Agiven poll states “54% of fifth graders read at or above the fifth-grade-level.” if there is a stated margin of error of +/- 2.5%, what is the 95% confidence interval for this statistic?

60.9774

step-by-step explanation:

because when you add 47.6 plus 7.32 equals 54.92

and when you add .0574 + 6= 6.0574

and when you add 54.92 and 6.0574 you get the answer of 60.9774.

plzz mark brainlest last one got deleted. cause i didn't explain it but i did but i understand what the mod meant