The coordinates of the vertices of a triangle are a(-1, 2), b(3, 1), and c(-3, -2). the coordinates of the vertices of its image are a'(3, -2), b(7, -3), and c'(1, -6). what transformations would result in this image?

δabc was translated up 4 units and right 4 units.
δabc was translated up 4 units and left 4 units.
δabc was translated right 4 units and down 4 units.
δabc was translated left 4 units and down 4 units.

step-by-step explanation:

for volume, add base x height x width

answer: integers are just whole numbers: positive, negative, and zero.

i = {-∞, -2, -1, 0, 1, 2, 3, ∞}

let x = 1st integer

let y = 2nd integer

x = 3y + 17   {equation 1}

xy = -24         {equation 2}

substitute 3y+17 in place of x n equation 2

and solve for y.

(3y+17)y = -24

3y2 + 17y = -24

3y2 + 17y + 24 = 0

from quadratic equation:

y = [-17±√(172-4(3)(24))]/(2(3))

y = (-17 ±√1)/6

y = (-17+1)/6   or     y = (-17-1)/6

y = -16/6           or     y = -18/6

y = -2 2/3         or   y = -3

since we are dealing with

y = -3

x = 3y+17 = -9+17 = 8

the integers are -3, 8

step-by-step explanation: