Zeros are x = β2, β3 .
Step-by-step explanation:
Given : f(x) = xΒ² + 5x + 6.
To find : What are the zeroes of f(x).
Solution : We have given that
f(x) = xΒ² + 5x + 6.
To find the zeros of the function we need to set f(x) = 0.
xΒ² + 5x + 6 = 0.
On factoring
xΒ² + 3x +2x + 6 = 0.
Taking common x from first two term and 2 from last two terms
x ( x + 3) +2 ( x +3) = 0.
On grouping
(x + 3) (x + 2) Β = 0
Now, x + 3 = 0 Β and x + 2 = 0
x = -3 and x = -2
Therefore, Zeros are x = β2, β3 .