The equation for the circle is:
x^2 + y^2 - 12x + 6y - 19 = 0

what is the center of the circle?

a. (-6, 3)
b. (12, -6)
c. (6, -3)
d. (-12, 6)

  C.  (6, -3)

Step-by-step explanation:

The x- and y-coordinates are the opposite of half the corresponding linear term coefficient:

  -(-12, 6)/2 = (6, -3)

This can be confirmed using a graphing calculator.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°