The equation h(t)=−16t2+120t+65 gives the height of a firework, in feet, t seconds after it is launched from a platform.
what is the height of the platform?
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ft

The height of the platform is 65 ft

Step-by-step explanation:

Let

t -----> the time in seconds after the launch of the fireworks from a platform

h(t) ----> the height of a firework in feet

we have

we know that

The height of the platform is when the value of t is equal to zero (y-intercept)

For t=0

therefore

The height of the platform is 65 ft

65 ft

Step-by-step explanation:

We are given that an equation which gives the height of firework

Where h(t)=Height in feet

t=Time in seconds

Substitute t= 0

When t= 0 then height of platform =h(0)

Hence, the height of platform=65 ft

65 ft

the least value out of the data shown is 5, maybe if you post a picture with it i could a little more.

step-by-step explanation:

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step-by-step explanation: