(ii only)

curve has an equation of y= 2x-1/x+1

i) find dy/dx (i do know this part)

ii) find the equation of the tangent to the curve at point a where the curve cuts the y-axis.

The equation of the tangent line can be found using slope formula and fact that slope = dy/dx.



where (x0,y0) is point A ---> (0,-1)

Then rearrange equation into slope-intercept form:


Finally sub in x=0 into dy/dx to get slope at the point (0,-1)