What is the connection between the y-intercept and the rule y=x^2-2x-8?

The x-intercepts are the ordered pairs that have values of 0 for the y-values.

Various methods exist:

1) Graphing
2) Quadratic Formula
3) Factoring

Let's factor. The coefficient of the x2 term is 1 so we can look at the constant term, −8 , and find its factors that add up to, 2 , the coefficient of the x term.

Factors of -8:

1+(−8)=−7 , Does not work
(−1)+8=7 , Does not work
2+(−4)=−2 , Does not work
(−2)+4=2 , Works because it is 2

0=(x−2)⋅(x+4)

Now set each factor equal to zero.

(x−2)=0
x=2

(x+4)=0
x=−4

The x-intercepts are (2,0) and (−4,0).

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

is only a line? i think so