Aspinner is divided into sections of equal size, some of which are red, some are blue, and the remaining are green. the probability of the arrow landing on a section colored red is 25%. the probability of the arrow landing on a section colored blue is 10%. what is the probability of the arrow landing on a section colored green?

The probability of the arrow landing on a section colored green is 65%.      

Step-by-step explanation:

Given : A spinner is divided into sections of equal size, some of which are red, some are blue, and the remaining are green.

The probability of the arrow landing on a section colored red is 25%.

The probability of the arrow landing on a section colored blue is 10%.

To find : The probability of the arrow landing on a section colored green

Solution :

→ The probability of the arrow landing on a section colored red is 25%.

i.e,

→ The probability of the arrow landing on a section colored blue is 10%.

i.e,

→ Probability of the spinner is P(R)+P(B)+P(G)=1

To find the probability of section green colored, substitute the value

Convert into percentage,

Therefore,The probability of the arrow landing on a section colored green is 65%.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify