The perimeter of a rectangle is 62 inches. if the length is one more than four times the width, what is the width of this rectangle?

We can represent the width as x. Then since the length is one more than four times the width, the length is 4x+1

We can plug these values into the perimeter equation: P=2L+2W and solve for x

62=2(4x+1)+2(x)
62=8x+2+2x (distribute)
62=10x+2 (combine like terms)
60 = 10x (subtract 2 from both sides)
x=6 (divide both sides by 10)

So the width is 6 inches

Hope this helps

/-/////////looks tough ‍♂️