Mathematics, 20.10.2019 21:30 stephanie37766
The area of the conference table in mr. nathan’s office must be no more than 175 ft2. if the length of the table is 18 ft more than the width, x, which interval can be the possible widths?
Answers: 2
Mathematics, 21.06.2019 18:20
Me solve this problem, and someone clearly explain to me how to solve it.1.) use the value of the discriminant to determine if the given trinomials has 2 real solutions, 1 real solution, or no real solutions.a. x2 − 4x − 7 = 0b. 4r2 + 11r − 3 = 0c. 3m2 + 7 = 0d. t2 + 2t + 1 = 0
Answers: 1
Mathematics, 21.06.2019 19:50
Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
Answers: 3
Mathematics, 22.06.2019 02:00
Ethan is proving that the slope between any two points on a straight line is the same. he has already proved that triangles 1 and 2 are similar. drag statements and reasons to complete the proof.
Answers: 1
The area of the conference table in mr. nathan’s office must be no more than 175 ft2. if the length...
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