3mangoes and 2 oranges have a mass of 200gm and 4 mangoes and 4 oranges have a mass of 300gm. find out the mass of each fruit.

Start by defining your variables
let x be the mass of a single mango in gm
let y be the mass of a single orange in gm

now, write the question as a system of equations

3 mango and 2 orange have a mass of 200 gm
3x +2y = 200
4 mango and 4 orange have a mass of 300 gm
4x +4y = 300

now you have a system of equations
3x+2y =200
4x+4y =300

solve for x and y

So, make two equations.

3m+2o=200
4m+4o=300

If you multiply the first equation by 2, you get 6m+4o=400.

You can take away the second equation from this so that you have
2m=100.

Therefore, m=50.

Substitute this into one of the first equations, I'm going to use the first one.

3(50)+2o=200
150+2o=200
2o=50
o=25

And finally, check by substituting into the second equation.

4(50)+4(25)=300
200+100=300

Hope this helps :)

Answer for 2: his profit would be $2.88 explanation: you have to first multiply 72 and 0.12 together to get $8.64 once you do that you know how much money the shopkeeper made from selling the candy bars individually. so you have to do 8.64-5.76=2.88 hope that ; )answer for 3: yeah i’m sorry i have no idea what number 3 is. i’m sorry i couldn’t with that.

All you have to do is multiply