Given the system of equations, what is the solution?

x + 3y = 5
x - 3y = -1

{(-4, -3)}
{(2, 1)}
{(-2, 3)}

Given the system of equations, what is the solution?

x + 3y = 5

x - 3y = -1

The answer is {(2, 1)}

x=2 and y=1

Step-by-step explanation:

We can find the solution in two ways,the first way is  by  term elimination the equations:

We can find x with the equation (3)

Now we can replace x=2 in the equation (1) to find y

Now, we have found x and y

x=2

y=1

The second way is  clearing x from equation 1

Now, we can replace in the equation (2)

Now, we can replace y=1 in the equation (1), (2) or (4) to find x

We will use the equation (1)

We have verified that by the two forms x = 2 and y = 1

step-by-step explanation:

options

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a