Aspinner has 10 equally sized sections, 4 of which are gray and 6 of which are blue. the spinner is spun twice. what is the probability that the first spin lands on blue and the second spin lands on gray.

 0.24

Step-by-step explanation:

We use the formula ,

Given : A spinner has 10 equally sized sections, 4 of which are gray and 6 of which are blue.

Event 1 : spin lands on blue

Event 2 : spin lands on gray

Since both the events are independent of each other , then the probability that the first spin lands on blue and the second spin lands on gray will be :-

Hence, the probability that the first spin lands on blue and the second spin lands on gray = 0.24

- "runner b is moving at a slower rate."

- "the graphs shown are graphs of distance(km) against time(min).

the slopes of this graphs are are given by:

slope = (change in y)/(change in x)

= (change in distance)/(change in time)

this is the formula for finding the speed. so, the slope of these graphs represent the speed of the runner.

taking each division in the graph to represent 1 on both axis:

runner a ⇒ speed = (2-0)/(1-0)

= 2/1

= 2 km/min

runner b ⇒ speed = (3-0)/(3-0)

= 3/3

= 1 km/min

this shows that   runner b is moving at a slower rate."