Changing volume if each edge of a cube is increasing at the constant rate of 3 centimeters per second, how fast is the volume increasing when x, the length of an edge, is 10 centimeters long?

Calculus! First one I've seen here! Take the derivative of the volume of a cube. Volume is V = s^3, dV = 3s^2 ds when s = 10 and ds = 3.  I think you used x. Anyway, in the derivative fill in the s with a 10 and the ds (rate of change) is 3. So dV = 3(10)^2 * 3
     dV = 600 cm per second